You can put this solution on YOUR website! x = 4y-3
(x)(y)=10
y(4y-3)=10
4y^2 - 3y = 10
4y^2 - 3y - 10 = 0
(4y+5)(y-2) = 0
4y+5=0 so y = -5/4
y-2=0 so y=2
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Using one of the numbers as 2
x=10/2 = 5
The numbers are 2 and 5
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