SOLUTION: A person must burn 3,500 calories to lose one pound of weight. a) Write an equation that represents the number of calories a person would have to burn daily to lose 4 pounds in

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Question 663091: A person must burn 3,500 calories to lose one pound of weight.
a) Write an equation that represents the number of calories a person would have to burn daily to lose 4 pounds in two weeks.
b) How many calories would the person have to burn each day?
Answer by ReadingBoosters(3246) About Me  (Show Source):
You can put this solution on YOUR website!
x = weight loss in lb
y = calories burned
...
(a)
calories burned / 3500 cal/lb = lbs lost
x = y/3500 which is the same as y = 3500x
if x is 4, then
y =4(3500) = 14,000 calories to burn
...
(b)
calories burned / 3500cal/lb)((2 weeks)/(14 days/2 weeks)) = lbs lost / day
..
x = (y/3500)(2/(14/2) which is the same as x=(y/3500)(14) or x=14y/3500
rearrange to solve for y
y = 3500x/14
if x = 4 pounds then
y = 4(3500)/14 = 1,000 lb/day
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