SOLUTION: 2sin(2θ)+ √ 3=0 interval [0,2π) ?

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Question 663061: 2sin(2θ)+ √ 3=0 interval [0,2π) ?
Answer by lwsshak3(11628) About Me  (Show Source):
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2sin(2θ)+ √ 3=0 interval [0,2π) ?
2sin(2θ)+ √ 3=0
sin(2θ)= √ 3/2
2θ=π/3 and 2π/3
θ=π/6 and π/3