SOLUTION: Someone please help me with this by tonight!!!! Suzanne is going to rent a car while she is out of town. One car rental company offers a flat rate of $35 per day plus $0.10 per mil

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Question 662890: Someone please help me with this by tonight!!!! Suzanne is going to rent a car while she is out of town. One car rental company offers a flat rate of $35 per day plus $0.10 per mile. Another rental company offers the same car for $25 per day plus $0.25 per mile. She will need the car for 5 days. How many miles would she need to drive for the first car company to be the better deal?
Please help and work the equation out the best you can!!!!!
Found 2 solutions by ReadingBoosters, Alan3354:
Answer by ReadingBoosters(3246) (Show Source):
You can put this solution on YOUR website!
Two plans
A = 35 + .1/mile
B = 25 + .25/mile
5 Day Rental
When is A 35 + .1x < 25 + .25x
35 - 25 < .25x - .1x
10 <.15x
x > 66.7 miles
Proof
35 + .1(66.7) = 41.7
25 + .25(66.7) = 41.7
At 66.7 or 67 miles the deals are the same, but greater than 67 miles the first deal is cheaper.
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Delighted to help.
-Reading Boosters
Wanting for others what we want for ourselves.

Answer by Alan3354(69443) (Show Source):
You can put this solution on YOUR website!
Suzanne is going to rent a car while she is out of town. One car rental company offers a flat rate of $35 per day plus $0.10 per mile. Another rental company offers the same car for $25 per day plus $0.25 per mile. She will need the car for 5 days. How many miles would she need to drive for the first car company to be the better deal?
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Car1 = 3500d + 10m
Car2 = 2500d + 25m
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C1 = C2
3500d + 10m = 2500d + 25m
1000d = 15m
d = 5
5000 = 15m
m = 5000/15 = 1000/3 miles the costs are equal
If she drives more than 1000/3 miles, Car 1 is the better deal (least cost)
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Car 2 might be a better car, or have a GPS, or some other factor.
$ per day and $ per mile only deal with costs, not comfort or convenience.
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In any case, NEVER buy the insurance from a rental agency.