SOLUTION: the perimeter of a rectangle is 40 ft. the length is 6 ft longer than the width. Find the dimensions. Write a system of linear equations and solve the resulting system. Let x be th
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Question 662812: the perimeter of a rectangle is 40 ft. the length is 6 ft longer than the width. Find the dimensions. Write a system of linear equations and solve the resulting system. Let x be the length and the y be the width.
write the first equation
2x+2y=
second equation
x=y+
what is the length
what is the width Answer by ReadingBoosters(3246) (Show Source):
You can put this solution on YOUR website! 2x+2y = 40
x = y + 6
2(y+6) + 2y = 40
2y + 12 + 2y = 40
4y = 28
y = 7 ft is the width
x = 7+6 = 13ft is the length
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