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Question 662730: 7a-4b-[5a-3{b-2(a-b)}]
Answer by ladyluck4772(11)   (Show Source):
You can put this solution on YOUR website! If you have trouble following the steps I show, I have given a detailed explaination following these steps.
7a-4b-[5a-3{b-2(a-b)}]
7a-4b-[5a-3{b-2a+2b}
7a-4b-[5a-3{3b-2a}
7a-4b-[5a-9b+6a]
7a-4b-[11a-9b]
7a-4b-1[11a-9b]
7a-4b-11a+9b
-4a+5b (your final answer)
Remember your order of operations first. What part of the problem do you work first? Whatever is inside the parentheses {}, which in this case is:
{b-2(a-b)}
However, there are () inside of {}. In this case you would multiply the 2 by (a-b) first.
{b-2a+2b} Plug this in the original equation where {b-2(a-b)} was. This leaves you with the rest of the problem to solve.
7a-4b-[5a-3{b-2a+2b] Now solve what is inside the brackets [].
7a-4b-[5a-3b+6a-6b]
Combine like terms inside the [] leaving:
7a-4b-[11a-9b]
Now drop the brackets and combine like terms. Be sure to distribute the negative sign (-) after the 4b before dropping the brackets.
7a-4b-[11a-9b]
7a-4b-11a+9b
-4a+5b (answer)
Please ask if have any questions. :)
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