SOLUTION: Ivan is three years older than his sister Mary. One-third of Ivan's age is two years less than one-half his sister's age one year ago. Find their age's now.

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Question 662667: Ivan is three years older than his sister Mary. One-third of Ivan's age is two years less than one-half his sister's age one year ago. Find their age's now.
Found 2 solutions by radh, kevwill:
Answer by radh(108) About Me  (Show Source):
You can put this solution on YOUR website!
Let's write this algebraically.
Ivan (I) is three years older (+3) than his sister Mary (M). [M+3=I]
One third (1/3) of Ivan's (I) age is 2 years less (-2) than one-half his sister's age (1/2M) one year ago (-1). [1/3I=1/2M-3]
We can now describe this as a system. Let's assume I is X and M is Y. Let's put our equations into x+y=# form.

M+3=I
M=I+3
M-I=3
-X+Y=3

1/3I=1/2M+3
2/3I=M+3
2/3I-M=3
2/3X-Y=3

Solved by pluggable solver: Using Cramer's Rule to Solve Systems with 2 variables



system%28-1%2Ax%2B1%2Ay=3%2C0.666666666666667%2Ax%2B-1%2Ay=3%29



First let A=%28matrix%282%2C2%2C-1%2C1%2C0.666666666666667%2C-1%29%29. This is the matrix formed by the coefficients of the given system of equations.


Take note that the right hand values of the system are 3 and 3 which are highlighted here:




These values are important as they will be used to replace the columns of the matrix A.




Now let's calculate the the determinant of the matrix A to get abs%28A%29=%28-1%29%28-1%29-%281%29%280.666666666666667%29=0.333333333333333. Remember that the determinant of the 2x2 matrix A=%28matrix%282%2C2%2Ca%2Cb%2Cc%2Cd%29%29 is abs%28A%29=ad-bc. If you need help with calculating the determinant of any two by two matrices, then check out this solver.



Notation note: abs%28A%29 denotes the determinant of the matrix A.



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Now replace the first column of A (that corresponds to the variable 'x') with the values that form the right hand side of the system of equations. We will denote this new matrix A%5Bx%5D (since we're replacing the 'x' column so to speak).


A%5Bx%5D=%28matrix%282%2C2%2Chighlight%283%29%2C1%2Chighlight%283%29%2C-1%29%29



Now compute the determinant of A%5Bx%5D to get abs%28A%5Bx%5D%29=%283%29%28-1%29-%281%29%283%29=-6. Once again, remember that the determinant of the 2x2 matrix A=%28matrix%282%2C2%2Ca%2Cb%2Cc%2Cd%29%29 is abs%28A%29=ad-bc



To find the first solution, simply divide the determinant of A%5Bx%5D by the determinant of A to get: x=%28abs%28A%5Bx%5D%29%29%2F%28abs%28A%29%29=%28-6%29%2F%280.333333333333333%29=-18



So the first solution is x=-18




---------------------------------------------------------


We'll follow the same basic idea to find the other solution. Let's reset by letting A=%28matrix%282%2C2%2C-1%2C1%2C0.666666666666667%2C-1%29%29 again (this is the coefficient matrix).




Now replace the second column of A (that corresponds to the variable 'y') with the values that form the right hand side of the system of equations. We will denote this new matrix A%5By%5D (since we're replacing the 'y' column in a way).






Now compute the determinant of A%5By%5D to get abs%28A%5By%5D%29=%28-1%29%283%29-%283%29%280.666666666666667%29=-5.



To find the second solution, divide the determinant of A%5By%5D by the determinant of A to get: y=%28abs%28A%5By%5D%29%29%2F%28abs%28A%29%29=%28-5%29%2F%280.333333333333333%29=-15



So the second solution is y=-15




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Final Answer:




So the solutions are x=-18 and y=-15 giving the ordered pair (-18, -15)




Once again, Cramer's Rule is dependent on determinants. Take a look at this 2x2 Determinant Solver if you need more practice with determinants.



There's no such thing as a negative age, so just flip that. That means Ivan is 18 and Mary is 15.

Hope this helps!


Answer by kevwill(135) About Me  (Show Source):
You can put this solution on YOUR website!
I think the original solver got this one wrong.
Let's let i = Ivan's age and m = Mary's age. Ivan is 3 years older than Mary, so
i+=+m+%2B+3
The next one is a little tricky. One third of Ivan's age is two years less than one half of his sister's age one year ago. So
i%2F3+=+%28m-1%29%2F2+-+2
To simplify the rest of the solution, let's multiply both sides of the above equation by 6:
6%2A%28i%2F3%29+=+%286%2A%28m-1%29%29%2F2+-+6%2A2
2%2Ai+=+%286%2Am+-+6%29%2F2+-12
2%2Ai+=+3%2Am+-+3+-+12
2%2Ai+=+3%2Am+-+15
Substituting m+3 for i (from the first equation) gives us
2%2A%28m%2B3%29+=+3%2Am+-+15
2%2Am+%2B+6+=+3%2Am+-+15
Subtract 2*m from both sides:
2%2Am+%2B+6+-+2%2Am+=+3%2Am+-+15+-+2%2Am
6+=+m+-+15
Add 15 to both sides:
6+%2B+15+=+m+-+15+%2B+15
21+=+m
So Mary is 21 and Ivan is 24.
We can check our answer by inserting our values for i and m into the original second equation:
24%2F3+=+%2821+-+1%29%2F2+-+2
8+=+20%2F2+-+2
8+=+10+-+2
8+=+8
So our calculations are correct.