SOLUTION: A circle has the equation 3(x-2)^2 + 3y^2 = 3 Find the center (h,k) and the radius r
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Question 662540
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A circle has the equation 3(x-2)^2 + 3y^2 = 3
Find the center (h,k) and the radius r
Answer by
stanbon(75887)
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A circle has the equation 3(x-2)^2 + 3y^2 = 3
Find the center (h,k) and the radius r
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Center: (2,0)
Radius: sqrt(3)
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Cheers,
Stan H.