SOLUTION: A chemist needs 7 liters of a 50% salt solution. All she has is a 20% salt solution and a 70% salt solution. How much of each of the two solutions should she mix to obtain her de

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Question 662527: A chemist needs 7 liters of a 50% salt solution. All she has is a 20% salt solution and a 70% salt solution. How much of each of the two solutions should she mix to obtain her desired solution?
Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
Let +a+ = liters of 20% solution needed
Let +b+ = liters of 70% solution needed
-----------
given:
(1) +a+%2B+b+=+7+
(2) +%28+.2a+%2B+.7b+%29+%2F+7+=+.5+
------------------------
(2) +.2a+%2B+.7b+=+.5%2A7+
(2) +2a+%2B+7b+=+35+
Multiply both sides of (1) by 2
and subtract (1) from (2)
(2) +2a+%2B+7b+=+35+
(1) +-2a+-+2b+=+-14+
+5b+=+21+
+b+=+21%2F5+
+b+=+4.2+
and, since
(1) +a+%2B+b+=+7+
(1) +a+%2B+b+=+35%2F5+
(1) +a+%2B+21%2F5+=+35%2F5+
(1) +a+=+14%2F5+
(1) +a+=+2.8+
2.8 liters of 20% solution is needed
4.2 liters of 70% solution is needed
check:
(2) +%28+.2a+%2B+.7b+%29+%2F+7+=+.5+
(2) +%28+.2%2A2.8+%2B+.7%2A4.2+%29+%2F+7+=+.5+
(2) +%28+.56+%2B+2.94+%29+%2F+7+=+.5+
(2) +3.5+%2F+7+=+.5+
(2) +3.5+=+.5%2A7+
(2) +3.5+=+3.5+
OK