SOLUTION: A man is 32 years older than his son. Ten years ago he was three times as old as his son was then. Find the present age of each.

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Question 662521: A man is 32 years older than his son. Ten years ago he was three times as old as his son was then. Find the present age of each.
Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
Let +f+ = Father's age
Let +s+ = Son's age
given:
+f+=+s+%2B+32+
+f+-+10+=+3%2A%28+s+-+10+%29+
----------------------
By substitution:
+s+%2B+32+-+10+=+3s+-+30+
+2s+=+32+%2B+30+-+10+
+2s+=+52+
+s=+26+
and, since
+f+=+s+%2B+32+
+f+=+26+%2B+32+
+f+=+58+
The Father is 58
The Son is 26
check:
+f+-+10+=+3%2A%28+s+-+10+%29+
+58+-+10+=+3%2A%28+26+-+10+%29+
+48+=+3%2A16+
+48+=+48+
OK