SOLUTION: A sample of 134 golfers showed that their average score on a particular golf course was 87.43 with a standard deviation of 4.53.
Answer each of the following (show all work
and
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-> SOLUTION: A sample of 134 golfers showed that their average score on a particular golf course was 87.43 with a standard deviation of 4.53.
Answer each of the following (show all work
and
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Question 662507: A sample of 134 golfers showed that their average score on a particular golf course was 87.43 with a standard deviation of 4.53.
Answer each of the following (show all work
and state the final answer to at least two decimal places.):
(A) Find the 99% confidence interval of the mean score for all 134 golfers.
(B) Find the 99% confidence interval of the mean score for all golfers if this is a sample of 105 golfers instead of a sample of 134.
(C) Which confidence interval is smaller and why
Hi,
134 golfers: m = 87.43 and s = 4.53
(A) Find the 99% confidence interval of the mean score for all 134 golfers.
ME =
the 99% confidence interval:
87.43 - ME < < 87.43 + ME
99% confidence interval of the mean score for all golfers if this is a sample of 105 golfers
ME =
87.43 - ME < < 87.43 + ME
(C) Which confidence interval is smaller and why
larger sample has a smaller confidence interval as the ME is smaller
