Question 662502: You find 8 coins in an old desk drawer, consisting entirely of nickels, dimes, and quarters, with a face value of 80 cents. However, the coins all date from 1889 and are worth much more than their face value. You were able to sell all the coins to a coin shop for a total of $22. Suppose you received $3 for each nickel, $2 for each dime, and $5 for each quarter. How many of the coins were quarters?
Answer by solver91311(24713)   (Show Source):
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Let  represent the number of nickels,  represent the number of dimes, and  represent the number of quarters.
because the total number of coins is 8
because the total FACE value of the coins is 80 cents, each nickel is worth 5 cents, each dime is worth 10 cents, and each quarter is worth 25 cents.
because the total SALE value of the coins is 22 dollars, each nickel is worth 3 dollars, each dime is worth 2 dollars, and each quarter is worth 5 dollars.
Solve the 3X3 system. Report the value of
John
My calculator said it, I believe it, that settles it
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