SOLUTION: Eric collected 1 1/3 times as many beads as Malik in the beginning. If Eric collected 48 more beads and Malik collected 13 more beads, Erc would have twice as many beads as Malik.

Algebra ->  Coordinate Systems and Linear Equations  -> Linear Equations and Systems Word Problems -> SOLUTION: Eric collected 1 1/3 times as many beads as Malik in the beginning. If Eric collected 48 more beads and Malik collected 13 more beads, Erc would have twice as many beads as Malik.       Log On


   

Question 662249: Eric collected 1 1/3 times as many beads as Malik in the beginning. If Eric collected 48 more beads and Malik collected 13 more beads, Erc would have twice as many beads as Malik. How many beads did they collect altogether in the beginning?
I feel as though the number of beads collected would look like this:
1 1/3(x)
And Malik's would just be an (x)
But I can't get any further, the rest of the problem confuses me.
Answer by ewatrrr(24785) About Me  (Show Source):
You can put this solution on YOUR website!
 

Hi,

Eric collected 1 1/3 times as many beads as Malik's highlight%28x%29in the beginning.

Malik's: x

Eric's: 1%261%2F3+x

If Eric collected 48 more beads1%261%2F3+x%2B48 and Malik collected 13 more beadsx%2B13

Erc would have twice as many beads as Malik.

1%261%2F3x%2B48+=+2%28x%2B13%29 

1%261%2F3x%2B48+=+2x%2B26%29 

          22+=+%282%2F3%29x

          66 = 2x

          33 = x, Malik's beginning amount. Eric's was 44.

How many beads did they collect altogether in the beginning? 33 + 44 = 77

and...

92+=+2%2A46