SOLUTION: 60% of the voters favor Ms. Stein. If 4 voters are chosen at random, find the probability that none support Ms. Stein, and the probability that at least one supports Ms. Stein.
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-> SOLUTION: 60% of the voters favor Ms. Stein. If 4 voters are chosen at random, find the probability that none support Ms. Stein, and the probability that at least one supports Ms. Stein.
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Question 662185: 60% of the voters favor Ms. Stein. If 4 voters are chosen at random, find the probability that none support Ms. Stein, and the probability that at least one supports Ms. Stein. Answer by stanbon(75887) (Show Source):
You can put this solution on YOUR website! 60% of the voters favor Ms. Stein. If 4 voters are chosen at random, find the probability that none support Ms. Stein, and the probability that at least one supports Ms. Stein.
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Binomial Problem with n = 4 and p(support) = 0.6 ; p(do not) = 0.4
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P(at least one supports) = 1 - P(none support)
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= 1 - 4C0(0.6)^0(0.4)^4
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= 1 - 0.4^4
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= 0.9744
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cheers,
Stan H.
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