Question 66211This question is from textbook College Algebra
: A ballet performance brought in $61,800 o the sale of 3000 tickets. If the tickets sold for $14 and $25, how many of each were sold?
This question is from textbook College Algebra
Answer by ptaylor(2198)   (Show Source):
You can put this solution on YOUR website! Let x=number sold for $25
Then 3000-x=number sold for $14
Now we are told that the amount brought in by the sale of the $25 tickets (25x) plus the amount brought in by the sale of the $14 tickets (14(3000-x)) was $61,800. So our equation to solve is:
25x+14(3000-x)=61,800 simplifying we have
25x+42,000-14x=61,800 collecting x's and subtracting 42,000 from each side:
11x=61,800-42,000 and
11x=19,800
x=1800 number of $25 tickets sold
3000-x=3000-1800=1200 number of $14 tickets sold
ck
1800(25)+1200(14)=61,800
45,000+16,800=61,800
61,800=61,800
Hope this helps---ptaylor
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