You can put this solution on YOUR website! x^2-16/2x^2+4x multiply x^2+9x+14/x^2+2x-8 divide x^2+3x-28/16x-8x^2
first
x^2-16 is the same as (x+4)(x-4)
next
2x^2+4x is the same as 2x(x+4)
then
x^2+9x+14 is the same as (x+7)(x+2)
then
x^2+2x-8 is the same as (x+4)(x-2)
then
x^2+3x-28 is the same as (x+7)(x-4)
last
16x-8x^2 is the same as -8x(x - 2)
Now begin...
[(x+4)(x-4)/2x(x+4)]times[(x+7)(x+2)/(x+4)(x-2)] divide [(x+7)(x-4)/-8x(x - 2)]
(x-4)/2x times [(x+7)(x+2)/(x+4)(x-2)] divide [(x+7)(x-4)/-8x(x - 2)]
(x-4)(x+7)(x+2)/2x(x+4)(x-2) divide [(x+7)(x-4)/-8x(x - 2)]
which is the same as
(x-4)(x+7)(x+2)/2x(x+4)(x-2) times -8x((x - 2)/(x+7)(x-4)
What remains after cancelling
-4(x+2)/ x+4
This expression has similied to [-4(x+2)]/(x+4)
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