SOLUTION: A radiator contains 8 quarts of fluid, 20% of which is antifreeze. How much fluid should be drained and replaced with pure antifreeze so that the new mixture is 25% antifreeze? (Ro

Algebra ->  Customizable Word Problem Solvers  -> Mixtures -> SOLUTION: A radiator contains 8 quarts of fluid, 20% of which is antifreeze. How much fluid should be drained and replaced with pure antifreeze so that the new mixture is 25% antifreeze? (Ro      Log On

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Question 662020: A radiator contains 8 quarts of fluid, 20% of which is antifreeze. How much fluid should be drained and replaced with pure antifreeze so that the new mixture is 25% antifreeze? (Round your answer to two decimal places.)
Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
Let +x+ = quarts of fluid to be drained
and replaced with pure antifreeze
+.2%2A8+=+1.6+ quarts of antifreeze to start with
--------------
+%281.6+-+.2x+%2B+x+%29+%2F+8+=+.25+
+%28+1.6+%2B+.8x+%29+%2F+8+=+.25+
+1.6+%2B+.8x+=+.25%2A8+
+1.6+%2B+.8x+=+2+
+.8x+=+.4+
+x+=+.5+
1/2 quart of fluid is to be drained
and replaced with pure antifreeze