SOLUTION: The length of a rectangle is 2 cm more than twice its width. If the perimeter of the rectangle is 52 cm, find the dimensions of the rectangle.
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Question 66178: The length of a rectangle is 2 cm more than twice its width. If the perimeter of the rectangle is 52 cm, find the dimensions of the rectangle. Answer by checkley71(8403) (Show Source):
You can put this solution on YOUR website! length=(2*width+2) & 2*length+2*width=52
2(2w+2)+2*w=52
4w+4+2w=52
6w=52-4
6w=48
w=48/6
w=8
proof
2(2*8+2)+2*8=52
2(16+2)+16=52
2*18+16=52
36+16=52
52=52
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