Hi,
Parabola: To graph, find x-intercepts,the Vertex, the line of symmertry and sketch it
f(x)= x^2 - 6x + 5,  , x = 1 & x = 5 are the x-intercepts
, x = 1 & x = 5 are the x-intercepts
f(x)= x^2 - 6x + 9 - 9 + 5 = (x-3)^2 - 4,  V(3,-4)  ||Putting into vertex form
the vertex form of a parabola:  where(h,k) is the vertex
 where(h,k) is the vertex
The 2nd g(x) = x^2 + 4x + 4 - 4 + 13 = (x+2)^2 + 9 has no x-intercepts, 
V(-2,9)  and x = -2 is the line of symmetry. Note: both Open Upward, a>0  
