SOLUTION: The length of a rectangle is 2 cm more than twice its width. If the perimeter of the rectangle is 52 cm, find the dimensions of the rectangle.

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Question 66170: The length of a rectangle is 2 cm more than twice its width. If the perimeter of the rectangle is 52 cm, find the dimensions of the rectangle.
Answer by algebrapro18(249) About Me  (Show Source):
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if the width is equal to x then the length is equal to 2x+2 which gives us the following equation:
2(2x+2) + 2x = 52

now solving the equation we get:

2(2x + 2) + 2x = 52
4x + 4 + 2x = 52
6x + 4 = 52
6x = 48
x = 8

so we know that the width is 8 and now we solve for the length

length = 2x+2
length = 2(8)+2
length = 18