SOLUTION: there is a sequence of three integers with a common difference of five. FOut times the largest integer minus twice the second largest integer is 108. FInd the three integers.

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Question 661547: there is a sequence of three integers with a common difference of five. FOut times the largest integer minus twice the second largest integer is 108. FInd the three integers.
Answer by ankor@dixie-net.com(22740) About Me  (Show Source):
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there is a sequence of three integers with a common difference of five.
Four times the largest integer minus twice the second largest integer is 108.
FInd the three integers.
:
The 3 integers: x, x+5, x+10
:
4(x+10) - 2(x+5) = 108
4x + 40 - 2x - 10 = 108
2x + 30 = 108
2x = 108 - 30
2x = 78
x = 78/2
x = 39, 44, 49; are the integers