SOLUTION: im giving the below function and im asked to find the domain and the intervals where f(x)>0.
f(x)=(e^x-1)ln(x)
i seemed to be stuck here
e^x-1>0
e^x=-1 -- now what do i do
Algebra ->
Exponential-and-logarithmic-functions
-> SOLUTION: im giving the below function and im asked to find the domain and the intervals where f(x)>0.
f(x)=(e^x-1)ln(x)
i seemed to be stuck here
e^x-1>0
e^x=-1 -- now what do i do
Log On
Question 661422: im giving the below function and im asked to find the domain and the intervals where f(x)>0.
f(x)=(e^x-1)ln(x)
i seemed to be stuck here
e^x-1>0
e^x=-1 -- now what do i do here?
x > 0=0
how do i even get started with finding where is greater then zero?
Thanks for all your help in advance.
Miguel
You can put this solution on YOUR website! im giving the below function and im asked to find the domain and the intervals where f(x)>0.
f(x)=(e^x-1)ln(x)>0
e^x-1>0
e^x>1
domain: (0,∞)
you can see this if you graph the e^x curve
..
ln(x)>0
domain: (1,∞)
you can see this if you graph the ln(x) curve
..
number line for f(x)
<.......0.......1===>
Domain of f(x) is (1,∞)
Domains of e^x and ln(x) must overlap
(