SOLUTION: The product of the opposite of 5 and a number is more than three plus the sum of twice the number and eleven. What is the greatest integer that satisfies this inequality?
we hav
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Question 661327: The product of the opposite of 5 and a number is more than three plus the sum of twice the number and eleven. What is the greatest integer that satisfies this inequality?
we have but not sure if this is correct:
-5n>3+(2n+11)
Thanks for the help! Answer by MathTherapy(10555) (Show Source):
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The product of the opposite of 5 and a number is more than three plus the sum of twice the number and eleven. What is the greatest integer that satisfies this inequality?
we have but not sure if this is correct:
-5n>3+(2n+11)
Thanks for the help!
Let the number be N
Opposite of 5 = - 5
- 5N > 3 + 2N + 11
– 5N – 2N > 11 + 3
– 7N > 14 ------- Changing inequality sign since divisor is negative (- 7)
Since N < - 2, then greatest integer to satisfy this inequality is: - 2 – 1, or
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