SOLUTION: please help me solve this problem. A chemist has two solutions of HNO3. One has 40% concentration and the other has 25% concentration. How many liters of each solution must be mixe
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-> SOLUTION: please help me solve this problem. A chemist has two solutions of HNO3. One has 40% concentration and the other has 25% concentration. How many liters of each solution must be mixe
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Question 660804: please help me solve this problem. A chemist has two solutions of HNO3. One has 40% concentration and the other has 25% concentration. How many liters of each solution must be mixed to ob tain 57 liters of a 26% solution? Answer by josmiceli(19441) (Show Source):
You can put this solution on YOUR website! Let = liters of 40% solution needed
Let = liters of 25% solution needed = liters of HN03 in 40% solution = liters of HN03 in 25% solution
------------------------------------
(1)
(2)
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(1)
(1)
(1)
Multiply both sides of (2) by
and subtract (2) from (1)
(1)
(2)
and, since
(2)
(2)
(2)
3.8 liters of 40% solution are needed
53.2 liters of 25% solution are needed
check:
(1)
(1)
(1)
(1)
(1)
OK
