SOLUTION: A solution containing 45% water is mixed with another solution containing 10% bromine. If the chemist needs 30 liters of the mixture, how many liters of each solution are needed to
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Question 660517: A solution containing 45% water is mixed with another solution containing 10% bromine. If the chemist needs 30 liters of the mixture, how many liters of each solution are needed to make a 34.5% water/bromine solution? Answer by stanbon(75887) (Show Source):
You can put this solution on YOUR website! A solution containing 45% water is mixed with another solution containing 10% bromine. If the chemist needs 30 liters of the mixture, how many liters of each solution are needed to make a 34.5% water/bromine solution?
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bromine + bromine = bromine
0.55x + 0.10(30-x) = 0.345*30
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55x + 10*30 - 10x = 34.5*30
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45x = 24.5*30
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x = 16 1/3 liters (amt. of 55% bromine solution needed)
30-x = 13 2/3 liters (amt. 10% bromine solution needed)
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Cheers,
Stan h.
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