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| Question 660475:  the length of a rectangle is 3 feet more than twice the width. the area is 90 square feet. what are the dimensions of the rectangle?
 
 Answer by ReadingBoosters(3246)
      (Show Source): 
You can put this solution on YOUR website! a = lw Equations
 l = 3 + 2w
 90 = lw
 Substitute the first into the second equation
 90 = (3+2w)w
 90 = 3w + 2w^2
 2w^2 + 3w - 90 = 0
 Multiples of 90: 30,3; 45,2; 18,5; 6,15
 Looking for combination where 2 x one of the pair will subtract from the other to yield 3
 (2w + 15)(w - 6)  Mixed signs due to - 90
 2w + 15 = 0; w = -15/2  NO
 w - 6 = 0; w = 6
 width = 6
 length = 3 + 2(6) = 15
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