SOLUTION: Martina leaves home at 9 A.M., bicycling at a rate of 24 mi/h. Two hours later, John leaves, driving at the rate of 48 mi/h. At what time will John catch up with Martina?

Algebra ->  College  -> Linear Algebra -> SOLUTION: Martina leaves home at 9 A.M., bicycling at a rate of 24 mi/h. Two hours later, John leaves, driving at the rate of 48 mi/h. At what time will John catch up with Martina?       Log On


   

Question 65999: Martina leaves home at 9 A.M., bicycling at a rate of
24 mi/h. Two hours later, John leaves, driving at the rate of 48 mi/h. At what time will John catch up with Martina?
Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
Martina leaves home at 9 A.M., bicycling at a rate of 24 mi/h.
Two hours later, John leaves, driving at the rate of 48 mi/h.
At what time will John catch up with Martina?
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Martina DATA:
In the 1st two hours Martina travels 48 miles.
After that she travels x miles.
Her total distance is x+48 miles
Her Rate is 24 mph.
Her time is (x+48)/24 hrs.
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John's DATA:
His distance must be the same as Martina's: x+48 miles
His Rate is 48 mph.
His time is (x+48)/48 hrs.
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EQUATIONn:
John's time = Martina's time-2
(x+48)/48 = (x+48)/24 -2
(x+48)=2(x+48)-96
x+48=96
x=48 miles
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Answer to question:
Martina time = (x+48)/24 = (96)/24=4 hrs
9:00+4 hrs = 1:00 PM
Cheers,
Stan H.