SOLUTION: the length of a rectangle is 2 feet less than twice the width. the area of a rectangle is 180 ft^2. find the length and width of the rectangle.

Algebra ->  Rectangles -> SOLUTION: the length of a rectangle is 2 feet less than twice the width. the area of a rectangle is 180 ft^2. find the length and width of the rectangle.      Log On


   



Question 659920: the length of a rectangle is 2 feet less than twice the width. the area of a rectangle is 180 ft^2. find the length and width of the rectangle.
Answer by ReadingBoosters(3246) About Me  (Show Source):
You can put this solution on YOUR website!
l = length
w = width
l = 2w - 2
A = (l)(w) = 180 ft^2
Substitute the first equation into the second
(2w - 2)w = 180
2w^2 - 2w = 180
2w^2 - 2w - 180
(2w - 20)(w + 9) mixed signs as the - 180
used multiple of 180: 9,20 where 2 times one minus the other yields 2
2w-20=0; 2w = 20; w = 10
w+9=0; w = -9 NO
Width is 10
Length is 2(10)-2 = 20-2= 18