SOLUTION: can someone explain how do i find the distance between this points: A=(6-1)B=(1,11) A=(-3,-5)B=(3,-13) A=(2,-2)B(-2,2) A=(4,-6)B=(-2,4)

Algebra ->  Triangles -> SOLUTION: can someone explain how do i find the distance between this points: A=(6-1)B=(1,11) A=(-3,-5)B=(3,-13) A=(2,-2)B(-2,2) A=(4,-6)B=(-2,4)      Log On


   

Question 659911: can someone explain how do i find the distance between this points:
A=(6-1)B=(1,11)
A=(-3,-5)B=(3,-13)
A=(2,-2)B(-2,2)
A=(4,-6)B=(-2,4)
Found 4 solutions by Alan3354, MathLover1, stanbon, ewatrrr:
Answer by Alan3354(69443) About Me  (Show Source):
You can put this solution on YOUR website!
can someone explain how do i find the distance between this points:
A=(6,-1)B=(1,11)
diffy = -1 - 11 = -12
diffx = 6 - 1 = 5
----
distance+=+sqrt%28diffy%5E2+%2B+diffx%5E2%29+=+sqrt%28144+%2B+25%29
distance = 13 units
======================
Do the others the same way.
A=(-3,-5)B=(3,-13)
A=(2,-2)B(-2,2)
A=(4,-6)B=(-2,4)

Answer by MathLover1(20850) About Me  (Show Source):
You can put this solution on YOUR website!

A=(6,-1) B=(1,11)

Solved by pluggable solver: Distance Formula to determine length on coordinate plane
The distance (d) between two points is given by the following formula:

d=sqrt%28%28x2-x1%29%5E2+%2B+%28y2-y1%29%5E2%29

Thus in our case, the required distance is
d=sqrt%28%281-6%29%5E2+%2B+%2811--1%29%5E2%29=+13+


For more on this concept, refer to Distance formula.



A=(-3,-5) B=(3,-13)

Solved by pluggable solver: Distance Formula to determine length on coordinate plane
The distance (d) between two points is given by the following formula:

d=sqrt%28%28x2-x1%29%5E2+%2B+%28y2-y1%29%5E2%29

Thus in our case, the required distance is
d=sqrt%28%283--3%29%5E2+%2B+%28-13--5%29%5E2%29=+10+


For more on this concept, refer to Distance formula.



A=(2,-2) B(-2,2)

Solved by pluggable solver: Distance Formula to determine length on coordinate plane
The distance (d) between two points is given by the following formula:

d=sqrt%28%28x2-x1%29%5E2+%2B+%28y2-y1%29%5E2%29

Thus in our case, the required distance is
d=sqrt%28%28-2-2%29%5E2+%2B+%282--2%29%5E2%29=+5.65685424949238+


For more on this concept, refer to Distance formula.



A=(4,-6) B=(-2,4)

Solved by pluggable solver: Distance Formula to determine length on coordinate plane
The distance (d) between two points is given by the following formula:

d=sqrt%28%28x2-x1%29%5E2+%2B+%28y2-y1%29%5E2%29

Thus in our case, the required distance is
d=sqrt%28%28-2-4%29%5E2+%2B+%284--6%29%5E2%29=+11.6619037896906+


For more on this concept, refer to Distance formula.

Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
can someone explain how do i find the distance between this points:
A=(6-1) ; B=(1,11)
distance = sqrt[(x-x1)^2 + (y-y1)^2]
-------
distance = sqrt[(11--1)^2 + (1-6)^2] = sqrt[144+25] = 13
------------------------------
A=(-3,-5)B=(3,-13)
dist = sqrt[(-13--5)^2+(3--3)^2] = sqrt[64+ 36] = 10
------------------------------
A=(2,-2)B(-2,2)
dist = sqrt[(2--2)^2 + (-2-2)^2] = sqrt[[16 + 16] = sqrt(32) = 4sqrt(2)
--------
A=(4,-6) ; B=(-2,4)
dist = sqrt(136) = 2sqrt(34)
==============================
Cheers,
Stan H.
==============

Answer by ewatrrr(24785) About Me  (Show Source):
You can put this solution on YOUR website!
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