SOLUTION: find four consecutive odd numbers whose sum is 432

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Question 659725: find four consecutive odd numbers whose sum is 432
Answer by fcabanski(1391) About Me  (Show Source):
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Call the first integer x. Each consecutive odd integer is two more than the last, so the four are x, x+2, x+4, x+6. Their sum is 432.


x+x+2+x+4+x+6 = 432


4x+12 = 432


4x = 420


x = 105


The integers are 105, 107, 109, 111

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