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Question 659587: Find three consecutive odd integers such that the sum of the smallest and largest is eleven less than three times the middle integer.
Answer by kevwill(135) (Show Source):
You can put this solution on YOUR website! Let x, x+2, and x+4 be the three consecutive odd integers. Then:
x + (x+4) = 3*(x+2) - 11
2x + 4 = 3x + 6 - 11
2x + 4 = 3x - 5
Subtracting 2x-5 from both sides:
2x + 4 - (2x - 5) = 3x - 5 - (2x - 5)
2x + 4 - 2x + 5 = 3x - 5 - 2x + 5
9 = x
So the three consecutive odd integers are 9, 11, and 13.
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