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| Question 659587:  Find three consecutive odd integers such that the sum of the smallest and largest is eleven less than three times the middle integer.
 Answer by kevwill(135)
      (Show Source): 
You can put this solution on YOUR website! Let x, x+2, and x+4 be the three consecutive odd integers.  Then: x + (x+4) = 3*(x+2) - 11
 2x + 4 = 3x + 6 - 11
 2x + 4 = 3x - 5
 Subtracting 2x-5 from both sides:
 2x + 4 - (2x - 5) = 3x - 5 - (2x - 5)
 2x + 4 - 2x + 5 = 3x - 5 - 2x + 5
 9 = x
 So the three consecutive odd integers are 9, 11, and 13.
 
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