SOLUTION: A vendor sells hot dogs and bags of potato chips. A customer buys 4 hot dogs and 3 bags of chips for $10.25. Another customer buys 5 hot dogs and 3 bags of potato chips for $12.2

Algebra ->  Customizable Word Problem Solvers  -> Misc -> SOLUTION: A vendor sells hot dogs and bags of potato chips. A customer buys 4 hot dogs and 3 bags of chips for $10.25. Another customer buys 5 hot dogs and 3 bags of potato chips for $12.2      Log On

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Question 659115: A vendor sells hot dogs and bags of potato chips. A customer buys 4 hot dogs and 3 bags of chips for $10.25. Another customer buys 5 hot dogs and 3 bags of potato chips for $12.25. Find the cost of each.
I started with:
x= price of a hot dog
y= price of chips
4x+3y=10.25
5x+3y=12.25
I do not know if this is correct or where to go from here.

Answer by MathTherapy(10552) About Me  (Show Source):
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A vendor sells hot dogs and bags of potato chips. A customer buys 4 hot dogs and 3 bags of chips for $10.25. Another customer buys 5 hot dogs and 3 bags of potato chips for $12.25. Find the cost of each.
I started with:
x= price of a hot dog
y= price of chips
4x+3y=10.25
5x+3y=12.25
I do not know if this is correct or where to go from here.

Yes, that is correct!!

You now have a system of equations in x and y that you need to solve to determine the value of each variable. You can begin by subtracting one from the other. This will give you the value of x, which should then be plugged into any of the two equations to determine the value of y. Do your check and you're "home-free."

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