SOLUTION: It takes Myline twice as long as Jeana to do a certain piece of work. Working together, they can finish the work in 6 hours. How long would it take Jeana to do it alone?

Algebra ->  Rate-of-work-word-problems -> SOLUTION: It takes Myline twice as long as Jeana to do a certain piece of work. Working together, they can finish the work in 6 hours. How long would it take Jeana to do it alone?      Log On


   

Question 658835: It takes Myline twice as long as Jeana to do a certain piece of work. Working together, they can finish the work in 6 hours. How long would it take Jeana to do it alone?
Answer by Edwin McCravy(20060) About Me  (Show Source):
You can put this solution on YOUR website!
It takes Myline twice as long as Jeana to do a certain piece of work. Working together, they can finish the work in 6 hours. How long would it take Jeana to do it alone?
Their combined rate is 1 job per 6 hours or %281_job%29%2F%286_hours%29 or 1%2F6job%2Fhour

Jeana's rate is 1 job per x hours or %281_job%29%2F%28x_hours%29 or 1%2Fxjob%2Fhour

Myline's rate is 1 job per 2x hours or %281_job%29%2F%282x_hours%29 or 1%2F%282x%29job%2Fhour

The equation comes from %28matrix%284%2C1%2C%0D%0A%0D%0A%22Jeana%27s%22%2C+rate%2C+in%2C+%22jobs%2Fhour%22%29%29 + %28matrix%284%2C1%2C%0D%0A%0D%0A%22Myline%27s%22%2C+rate%2C+in%2C+%22jobs%2Fhour%22%29%29 = %28matrix%285%2C1%2C%0D%0A%0D%0ATheir%2C+combined%2C+rate%2C+in%2C+%22jobs%2Fhour%22%29%29

                                     1%2Fx + 1%2F%282x%29 = 1%2F6

Multiply through by LCD = 6x and solve.  You'll get 9 hours.

Edwin