SOLUTION: In a group of 15 boys, there are 6 scouts. In how many ways can 8 boys be selected, so as to include
(i) exactly 3 scouts
(ii) at least 3 scouts
(iii) at the most 3 scout
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-> SOLUTION: In a group of 15 boys, there are 6 scouts. In how many ways can 8 boys be selected, so as to include
(i) exactly 3 scouts
(ii) at least 3 scouts
(iii) at the most 3 scout
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Question 658812: In a group of 15 boys, there are 6 scouts. In how many ways can 8 boys be selected, so as to include
(i) exactly 3 scouts
(ii) at least 3 scouts
(iii) at the most 3 scouts
Hi,
Example of BIONOMIAL PROBABILITY DISTRIBUTION
Note: The probability of x successes in n trials is:
P = nCx* where p and q are the probabilities of success and failure respectively.
In this case p(scout) = 2/5 & q = 3/5 and n = 8
nCx =
8 boys be selected, so as to include
P(x = 3) = 8C3(.4)^3(.6)^5
P(x ≥ 3) = 1- P(x≤ 2)= 1 - P(x=0) + P(x=1)+ P(x=2)
P(x ≤ 3) = P(x=0) + P(x=1)+ P(x=2)+ P(x=3)
