One angle of a triangle is twice another.
The third angle is three times the smallest.
Find the measure of the smallest angle.
Let the smallest angle be A
Let the middle-sized angle be B
Let the largest angle be C.
There are two possibilities because the first
sentence is ambiguous.
1. If the middle-sized angle is twice the
smallest angle, then,
B = 2A
C = 3A
A + B + C = 180
Do you know how to solve that system of
equations? If not post again asking how.
Solve that system and get
A = 30°, B = 60°, C = 90°
so the smallest angle is A or 30°.
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2. If the largest angle is twice the
middle-sized angle, then
C = 2B
C = 3A
A + B + C = 180
Solve that system and get:
A = 32 8/11°, B = 49 1/11°, 98 2/11°
so the smallest angle is 32 8/11°
Edwin
