SOLUTION: For this problem in Newtons law of cooling, what does the e mean? Why do we use ln and what is ln? T (t) = Te + (T0 − Te ) e^-kt 160= 69 + (190-69)e^k2 160-69 = 69-69

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Question 658621: For this problem in Newtons law of cooling, what does the e mean? Why do we use ln and what is ln?
T (t) = Te + (T0 − Te ) e^-kt
160= 69 + (190-69)e^k2
160-69 = 69-69(121)e^k2
91 = (121)ek2
91/121 = (121/121)e^2k
e^2k = 91/121
2k = ln(91/121)
k = .5(ln(91/121))
k = .5(-.284931)
k = -.1425
69 + (180 - 69)e^-.1425t = 130
69-69 + 121e-.1425t = 130-69
121e.-1425t = 61
e^-.1425t = 61/121
-.1425t = ln(61/121)
t = (-.684917)/(-.1425)
t = 4.8 minutes

Found 2 solutions by stanbon, MathLover1:
Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
For this problem in Newtons law of cooling, what does the e mean? Why do we use ln and what is ln?
T (t) = Te + (T0 − Te ) e^-kt
T(t) is he temperature of the object at time "t".
Te is the temperature of the environment.
To is the temperature of the object at some initial time (e.g. time of death)
-----
The e in e^kt is the irrational number e = 2.718281828...
------------------------------
160= 69 + (190-69)e^k2
160-69 = 69-69(121)e^k2
91 = (121)ek2
91/121 = (121/121)e^2k
e^2k = 91/121
2k = ln(91/121)
---
ln is the "natural log"; it is the power of "e" that gives you some
particular number.
For example:
ln(e^k2) = k2
ln(5) = 1.609.. because e^(1.609..) = 5
--------------------------------
------------
k = .5(ln(91/121))
k = .5(-.284931)
k = -.1425
69 + (180 - 69)e^-.1425t = 130
69-69 + 121e-.1425t = 130-69
121e.-1425t = 61
e^-.1425t = 61/121
-.1425t = ln(61/121)
t = (-.684917)/(-.1425)
t = 4.8 minutes
===================
Cheers,
Stan H.

Answer by MathLover1(20850) About Me  (Show Source):
You can put this solution on YOUR website!
The number e is an important mathematical constant,
approximately equal to 2.71828, that is the base of
the natural logarithm ln.
eis important simply because it has all those nice properties
you've been studying. Whenever you take the derivative of e%5Ex
(that's e to the x), you get e%5Ex back again
It's the only function on Earth that will do that (except things
like 5%2A+e%5Ex and variants like that). That's pretty cool stuff.
Exponentially+changing functions are written as e%5Ex,
where a represents the rate of the exponential change.
In such cases where exponential changes are involved we usually use
another kind of logarithm called natural+logarithm.
The natural+logarithm can be thought of as Logarithm+Base-e. What this means is that it is a logarithmic operation
that when carried out on e raised to some+power gives
us the power+itself.
This logarithm is labeled with ln (for "natural log") and its definition is: ln%28e%5Ex%29+=+x.