SOLUTION: Hi! I need some help to simplify and reduce to lowest terms (w/45)+[(3w+2)/30] and [1/(10a^3b)]+[4/(ac^3)] thanks so much for your help in advance!!

Algebra ->  Polynomials-and-rational-expressions -> SOLUTION: Hi! I need some help to simplify and reduce to lowest terms (w/45)+[(3w+2)/30] and [1/(10a^3b)]+[4/(ac^3)] thanks so much for your help in advance!!      Log On


   

Question 65856: Hi! I need some help to simplify and reduce to lowest terms
(w/45)+[(3w+2)/30]
and
[1/(10a^3b)]+[4/(ac^3)]
thanks so much for your help in advance!!
Answer by funmath(2933) About Me  (Show Source):
You can put this solution on YOUR website!
Hi! I need some help to simplify and reduce to lowest terms
(w/45)+[(3w+2)/30]
The prime factors of 45 are: 3*3*5
The Prime factors of 30 are:2*3*5
Therefore the LCD is:2*3*3*5=90
2w%2F%282%2A45%29%2B3%283w%2B2%29%2F%283%2A30%29
2w%2F90%2B%289w%2B6%29%2F90
%282w%2B9w%2B6%29%2F90
highlight%28%2811w%2B6%29%2F90%29
and
[1/(10a^3b)]+[4/(ac^3)]
The prime factors of 10a^3b are 2*5*a^3b
the prime factors of ac^3 are ac^3
The LCD is: 2*5*a^3bc^3=10a^3bc^3
1%2Ac%5E3%2F%28c%5E3%2810a%5E3%2Ab%29%29%2B4%2A10a%5E2b%2F%2810a%5E2%2Ab%28ac%5E3%29%29
c%5E3%2F%2810a%5E3%2Abc%5E3%29%2B40a%5E2%2Ab%2F%2810a%5E3%2Abc%5E3%29
highlight%28%28c%5E3%2B40a%5E2%2Ab%29%2F%2810a%5E3%2Abc%5E3%29%29
Happy Calculating!!!!