SOLUTION: Hi, here's my question and what I've come up with so far, I think I'm overcomplicating it though. A rectangular storage unit has dimension 1m by 2m by 3m. If each linear dimensi

Algebra ->  Coordinate Systems and Linear Equations  -> Linear Equations and Systems Word Problems -> SOLUTION: Hi, here's my question and what I've come up with so far, I think I'm overcomplicating it though. A rectangular storage unit has dimension 1m by 2m by 3m. If each linear dimensi      Log On


   



Question 65854: Hi, here's my question and what I've come up with so far, I think I'm overcomplicating it though.
A rectangular storage unit has dimension 1m by 2m by 3m. If each linear dimension is increased by the same amount:
a) what increase would result in a new storage unit with a volume 10 times its original?
I've come up with: +%28x%29%28x%2B2%29+%28x%2B3%29+=+10y+
At this point I'm not sure how to proceed next I tried expanding it to:
+x%5E3+%2B+5x%5E2+%2B+6x+%2B+0+=+10y+
I learned about factors recently so I could try finding factors but the only factors of 0 are 0 so I think I'm making a mess of this word problem.

Answer by funmath(2933) About Me  (Show Source):
You can put this solution on YOUR website!
Hi, here's my question and what I've come up with so far, I think I'm overcomplicating it though.
A rectangular storage unit has dimension 1m by 2m by 3m. If each linear dimension is increased by the same amount:
a) what increase would result in a new storage unit with a volume 10 times its original?
First notice that the original volume is: 1(2)(3)=6m^3, so ten times that amount would be 10(6m^3)=60m^3
If each linear dimension is increased by the same amount you'd have:
(x+1)(x+2)(x+3)=60
x^3+6x^2+11x+6=60
x^3+6x^2+11x-54=0
The factors you get to try are+-2,3,6,9,18,27,54
%28x%5E3%2B6x%5E2%2B11x-54%29%2F%28x-2%29=x%5E2%2B8x%2B27 which is prime, so
highlight%28x=2%29m
Happy Calculating!!!