SOLUTION: Find all real solutions of equation 4x^2+4x−4=0.

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Question 658525: Find all real solutions of equation 4x^2+4x−4=0.
Answer by MathLover1(20849) About Me  (Show Source):
You can put this solution on YOUR website!
4x%5E2%2B4x-4=0
x+=+%28-b+%2B-+sqrt%28+b%5E2-4%2Aa%2Ac+%29%29%2F%282%2Aa%29+...note that a=4, b=4 and c=-4
x+=+%28-4+%2B-+sqrt%28+4%5E2-4%2A4%2A%28-4%29+%29%29%2F%282%2A4%29+

x+=+%28-4+%2B-+sqrt%28+16-16%28-4%29+%29%29%2F8+

x+=+%28-4+%2B-+sqrt%28+16%2B64+%29%29%2F8+

x+=+%28-4+%2B-+sqrt%28+80+%29%29%2F8+

x+=+%28-4+%2B-+8.9%29%2F8+

solutions:
x+=+%28-4+%2B+8.9%29%2F8+

x+=+%284.9%29%2F8+

highlight%28x+=+0.6125%29
or
x+=+%28-4+-8.9%29%2F8+

x+=+%28-12.9%29%2F8+

highlight%28x+=+-1.6125%29