SOLUTION: What are the x, y, and z values for the problems:3x+2y+z=7, 5x+5y+4z=3, 3x+2y+3z=1, and how to solve to get those values?

Algebra ->  Linear-equations -> SOLUTION: What are the x, y, and z values for the problems:3x+2y+z=7, 5x+5y+4z=3, 3x+2y+3z=1, and how to solve to get those values?      Log On


   

Question 658034: What are the x, y, and z values for the problems:3x+2y+z=7, 5x+5y+4z=3, 3x+2y+3z=1, and how to solve to get those values?
Answer by ewatrrr(24785) About Me  (Show Source):
You can put this solution on YOUR website!
 

Hi,

3x+2y+z=7, 5x+5y+4z=3, 3x+2y+3z=1



3x+2y+z=7

3x+2y+3z=1  || Subtract 2nd from 1st

  -2z = 6

    z = -3



3x+ 2y = 10    ||multiply 1st EQ by 5 and subtract from 3 times the 2nd EQ

5x + 5y = 15

       5y = -5

        y = -1  and x = 4

and...Using 3x+2y+3z=1

 12+-+2+-+9+=+1