SOLUTION: Given: <EAT and <DAT are adjacent Given: <EAT is 5x larger than <DAT Given: <EAT = 5x Given: <DAT = 4y Given: <EAD = 6y+4x+4 What is the value for x and y? If this was a

Algebra ->  Angles -> SOLUTION: Given: <EAT and <DAT are adjacent Given: <EAT is 5x larger than <DAT Given: <EAT = 5x Given: <DAT = 4y Given: <EAD = 6y+4x+4 What is the value for x and y? If this was a       Log On


   

Question 658001: Given: Given: Given: Given: Given: What is the value for x and y?
If this was a supplemental or complementary angle then I could plug in 90 or 180, but it doesnt say they are or are not. So; 5x+4y=6y+4x+4... when I do this and solve for x or y then plug in the number to the equation it always equals zero, which it should cause they are equal. I used process of elimination to find the answer but cannot figure out how to set up the equation correctly, and where does the 5x larger < come into play? If I am stuck...Thanks,,,
Answer by MathLover1(20850) About Me  (Show Source):
You can put this solution on YOUR website!
Given: <EAT and <DAT are adjacent
Given: <EAT is 5x larger than <DAT
Given: <EAT+=+5x
Given: <DAT+=+4y
Given: <EAD+=+6y%2B4x%2B4
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Given: <EAT+=+5x
Given: <DAT+=+4y
if <EAT is 5x larger than <DAT, and if given that <EAT+=+5x and <DAT+=+4y, then
5x%2B+5x+=4y
10x=4y.......solve for x..->...x=%284%2F10%29y=%282%2F5%29y
it is also given that:
6y%2B4x%2B4=5x%2B4y....plug in x=%282%2F5%29y and solve for y
6y%2B4%2A%282%2F5%29y%2B4=5%2A%282%2F5%29y%2B4y
6y%2B1.6y%2B4=2y%2B4y
6y%2B1.6y-2y-4y=-4
7.6y-6y=-4
1.6y=-4
y=-4%2F1.6
highlight%28y=-2.5%29.............negative angle (rotates in clockwise direction)
find x:
x=%282%2F5%29%28-2.5%29
x=-1...........also negative angle.

check:
6y%2B4x%2B4=5x%2B4y
6%28-2.5%29%2B4%28-1%29%2B4=5%28-1%29%2B4%28-2.5%29
-15-4%2B4=-5-10
-15=-15
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<EAT is 5x larger than <DAT
5x%2B+5x+=4y
-5-5=4%28-2.5%29
-10=-10