SOLUTION: The greenhouse cools down after the sun sets to the following formula T=85-(n^2-1)/(n+1), where n is the number of hours the sun after the stops hitting the building. In December t
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-> SOLUTION: The greenhouse cools down after the sun sets to the following formula T=85-(n^2-1)/(n+1), where n is the number of hours the sun after the stops hitting the building. In December t
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Question 65795: The greenhouse cools down after the sun sets to the following formula T=85-(n^2-1)/(n+1), where n is the number of hours the sun after the stops hitting the building. In December the average number of hours that the sun does not hit the greenhouse is 16.25. How cool should we expect the greenhouse to get by sunrise of an average day in December? Answer by ankor@dixie-net.com(22740) (Show Source):
You can put this solution on YOUR website! The greenhouse cools down after the sun sets to the following formula T=85-(n^2-1)/(n+1), where n is the number of hours the sun after the stops hitting the building. In December the average number of hours that the sun does not hit the greenhouse is 16.25. How cool should we expect the greenhouse to get by sunrise of an average day in December?
:
Assume that the number of dark hrs after sun-set and before sunrise is 16.25 hrs.
n = 16.25
:
T = 85 - (n^2 - 1) / (n+1)
:
T = 85 - (16.25^2 - 1) / (16.25 + 1)
:
T = 85 - (264.0625 - 1) / 17.25
:
T = 85 - (263.0625/17.25)
:
T = 85 - 15.25
:
T = 69.75
