Question 657944: how can i find the value of y?
4^2y + 4^(2y-1) = 4 Found 3 solutions by Alan3354, Edwin McCravy, MathLover1:Answer by Alan3354(69443) (Show Source):
You can put this solution on YOUR website! how can i find the value of y?
4^2y + 4^(2y-1) = 4
-----------------------
(2y-1)*log(4) = log(0.8)
2y-1 = log(0.8)/log(4)
y = (log(0.8)/log(4) + 1)/2
+ =
We use the principle that on the second term:
+ =
We change the to + =
Multiply through by 4 to remove the fraction:
+ = + = + =
The two terms on the left are like terms and combine as
=
Then we divide both sides by 5
=
Now we take logs of both sides
=
We use the principle =
Divide both sides by = = 0.4195179763
Edwin