SOLUTION: Hi! I need to state the domain for 1. 6/4x^3 2. (x+5)/(x^2-36) 3. (x+5)/(x^2+36) Thanks!

Algebra ->  Functions -> SOLUTION: Hi! I need to state the domain for 1. 6/4x^3 2. (x+5)/(x^2-36) 3. (x+5)/(x^2+36) Thanks!      Log On


   



Question 65784: Hi! I need to state the domain for
1. 6/4x^3
2. (x+5)/(x^2-36)
3. (x+5)/(x^2+36)
Thanks!

Answer by funmath(2933) About Me  (Show Source):
You can put this solution on YOUR website!
These are rational expressions, the domain of rational expressions contain anything EXCEPT what will make the denominator (bottom) equal 0.
1. 6/4x^3
6%2F4x%5E3
The restricted values are found by setting the denominator equal to 0 and solving for x:
4x%5E3=0
4x%5E3%2F4=0%2F4
x%5E3=0
cubed root (x^3)= cubed root (0)
x=0
The domain is all real numbers except 0.
{x|x not= 0} <---set builder notation
(-infinity,0)U(0,infinity) <--interval notation
:
2. (x+5)/(x^2-36)
x%5E2-36=0
x%5E2-36%2B36=0%2B36
x%5E2=36
sqrt%28x%5E2%29=%2B-sqrt%2836%29
x=-6 or x=6
{x|x not= +\- 6}
(-infinity,-6)U(-6,6)U(6,infinity)
:
3. (x+5)/(x^2+36)
x%5E2%2B36=0
x%5E2%2B36-36=0-36
x%5E2=-36
sqrt%28x%5E2%29=%2B-sqrt%28-36%29
This results in no real number solution, therefore the domain for this is ALL REAL NUMBERS.
{x|x=R}
(-infinity,infinity)
Happy Calculating!!!