SOLUTION: Solve for x: log base 2(x^2+7x)=3

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Question 657831: Solve for x:
log base 2(x^2+7x)=3
Answer by lwsshak3(11628) About Me  (Show Source):
You can put this solution on YOUR website!
Solve for x:
log base 2(x^2+7x)=3
log2(8)=3
log2(x^2+7x)=log2(8)
x^2+7x=8
x^2+7x-8=0
(x+8)(x-1)=0
x=-8
or
x=1