SOLUTION: Two planes make a 1000 mile flight, one flying 75 miles per hour faster than the other. The quicker plane makes the trip 3 hours faster. How long did it take the slower plane to c
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Question 657689: Two planes make a 1000 mile flight, one flying 75 miles per hour faster than the other. The quicker plane makes the trip 3 hours faster. How long did it take the slower plane to complete the flight? Answer by kevwill(135) (Show Source):
You can put this solution on YOUR website! Let s be the speed of the slower plane and s+75 be the speed of the faster plane.
The time it takes the slower plane to make the flight is
The time it takes the faster plane to make the flight is
The difference in these two times is 3 hours, so
We can solve for s using the quadratic equation with a=1, b=75, and c=-25000
So s = -200 or s = 125. We'll ignore the negative answer because the planes are not flying backward.
So the slower plane is flying at 125 mph and completes the trip in 8 hours.
The faster plane is flying at 200 mph and completes the trip in 5 hours.
