Question 657563: Can you solve this problem?:
Paul is 20 years older than EVan. Ten years ago, Pau lwas twice as old as Evan was then. How old is each now?
Answer by kevwill(135)   (Show Source):
You can put this solution on YOUR website! Let p be Paul's age and q be Evan's age. Paul is 20 years older than Evan, so:
p = q + 20
Ten years ago, Paul was twice as old as Even was then, so:
(p - 10) = 2 * ( q - 10), or
p - 10 = 2 * q - 20
Substituting q + 20 for p, we have:
q + 20 - 10 = 2 * q - 20
q + 10 = 2 * q - 20
Subtracting q from and adding 20 to each side:
q + 10 - q + 20 = 2 * q - 20 - q + 20
30 = q
So Evan is 30 years old, and Paul is 30+20 = 50 years old.
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