Question 657243: A family has 4 children. Using a tree diagram that shows how many ways the children could have been born, from first to last born, determine how many ways the family could have had 2 boys and 2 girls.
Answer by stanbon(75887) (Show Source):
You can put this solution on YOUR website! A family has 4 children. Using a tree diagram that shows how many ways the children could have been born, from first to last born, determine how many ways the family could have had 2 boys and 2 girls.
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Binomial Problem with n = 4 and p(boy) = P(girl) = 1/2
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P(x = 2 girls) = 4C2(1/2)^2*(1/2)^2 = 6/16 = 3/8
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Note: If there are 2 girls in a family of 4, the other 2 children must be boys.
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Cheers,
Stan H.
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