SOLUTION: 4 married couples have 8 seats in arrow at the theater, starting at an aisle seat. In how many ways can they arrange themselves if no couple is to be separated?

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Question 657235: 4 married couples have 8 seats in arrow at the theater, starting at an aisle seat. In how many ways can they arrange themselves if no couple is to be separated?
Answer by kevwill(135) About Me  (Show Source):
You can put this solution on YOUR website!
There are 4! = 4*3*2*1 = 24 ways to arrange the couples.
For each couple, there are 2 different ways they can sit: one on the left and the other on the right, or vice-versa.
With 4 couples, there are 2%5E4 = 16 ways they can sit for each arrangement.
So the total number of different ways they can arrange themselves is:
4%21%2A2%5E4+=+24%2A16+=+384